When adding the square root of 16 and -8 which type of number is the sum?

Question

A. Integer
B. Irrational number
C. Radical
D. Whole number

Answer 1

I interpret
"adding the square root of 16 and -8"
as
"adding the square root of 16 and the square root of -8"
which gives
sqrt(16)+sqrt(-8)
= 4+2√2 i
which is a complex irrational number.

If I interpret
"adding the square root of 16 and -8"
as
"the square root of the sum of 16 and -8", then
the result is
√(16-8)=√8=2√2
which is an irrational number.

You may be in a better position to judge what your teacher means.

Answer 2

Is this right

Answer 3

Can someone please help me with the rest of the anwsers send them to me on Instagram @jacob_is_santa_24

Answer 4

square root of 16 and adding it to negative 8 makes -4
It would count as a integer