y = vt - 4.9t^2
max height h is at t = v/9.8, so
h = v^2/19.6
v^2 = 50*19.6
v = 31.3 m/s
When a stone is thrown upwards with an initial velocity of v metres per second, it reaches a maximum height of h metres.
h is directly proportional to the square of v.
Calculate the value of v when h = 50
Please help
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