When a pendulum with a period of 2.00000 s is moved to a new location from one where the acceleration of gravity was 9.80 m/s2, its new period becomes 1.99711 s. By how much does the acceleration of gravity differ at its new location? (m/s2)

Answer 1

T=2πsqrt(L/g),
T₁=2πsqrt(L/g₁),

(T/T₁)²=g₁/g,
g₁ = g(T/T₁)² =…

Answer 2

9.816