When a particle located a distance x feet from the origin, a force of x^2+2x pounds acts on it. How much work is done in moving it from x=1 to x=3?

Answer 1

W=[1,3]∫(x^2+2x)dx
W=[(x^3)/3+(2x^2)/2]
W=27/3+9-(1/3-1)
W=9+9-1/3-1=50/3pound/feet