When a mass of 28 g is attached to a certain
spring, it makes 19 complete vibrations in
3.9 s.
What is the spring constant of the spring?
Answer in units of N/m
2 answers
a
The spring constant of the spring can be calculated using the formula:
k = (4π²m)/T²
where k is the spring constant in N/m, m is the mass in kg, and T is the time period in seconds.
First, we need to find the time period of one complete vibration:
T = (3.9 s) / (19 vibrations)
T = 0.2053 s/vibration
Now, we can use this time period and the given mass to find the spring constant:
k = (4π² * 0.028 kg) / (0.2053 s/vibration)²
k = 7.65 N/m
Therefore, the spring constant of the spring is 7.65 N/m.
k = (4π²m)/T²
where k is the spring constant in N/m, m is the mass in kg, and T is the time period in seconds.
First, we need to find the time period of one complete vibration:
T = (3.9 s) / (19 vibrations)
T = 0.2053 s/vibration
Now, we can use this time period and the given mass to find the spring constant:
k = (4π² * 0.028 kg) / (0.2053 s/vibration)²
k = 7.65 N/m
Therefore, the spring constant of the spring is 7.65 N/m.
2 answers