Vo = 240km/h = 240,000m/3600s = 66.7 m/s
V^2 = Vo^2 + 2a*d
a = (V^2-Vo^2)/2d = (0-(66.7^2))190 =
23.42 m/s^2.
When a jet lands on an aircraft carrier, a hook on the tail of the plane grabs a wire that quickly brings the plane to a halt before it overshoots the deck. In a typical landing, a jet touching down at 240 km/h is stopped in a distance of 95 m. What is the magnitude of the jet's acceleration as it is brought to rest?
2 answers
-23.4