When a charged particle moves at an angle of 12° with respect to a magnetic field, it experiences a magnetic force of magnitude F. At what angle (less than 90°) with respect to this field will this particle, moving at the same speed, experience a magnetic force of magnitude 1.8F?

Answer 1

F=qvB sin12⁰
1.8F=qvBsinφ

sinφ/sin12⁰ =1.8

sinφ =sin12⁰•1.8=0.208•1.8=0.374
φ=sin⁻¹0.374=22⁰