When a baseball is at rest and then is thrown, what is the relationship between the ball's potential and kinetic energy?

A. As the ball's potential energy decreases, its kinetic energy decreases.
B. As the ball's potential energy increases, its kinetic energy decreases.
C. As the ball's potential energy decreases, its kinetic energy increases.
D. As the ball's potential energy increases, its kinetic energy increases.

3 answers

The correct answer is C. As the ball's potential energy decreases, its kinetic energy increases.

When a baseball is at rest and is thrown, it typically starts from a position where it has some potential energy (due to its height) and, as it is thrown, this potential energy decreases (if we consider a slight drop in height during the throw) while kinetic energy increases as the ball gains speed. Hence, there is a conversion of energy from potential to kinetic in the context of throwing the ball.

are you sure this is correct

Let me clarify the concepts related to potential and kinetic energy in the context of a thrown baseball.

When a baseball is at rest (e.g., held in someone's hand), it has gravitational potential energy if it is above ground level. When that baseball is thrown, it accelerates and gains speed, which means it is converting energy into kinetic energy.

  1. As the baseball is thrown, assuming there's no significant change in height (it is mostly being thrown horizontally), the potential energy associated with its height remains relatively constant during the act of throwing.

  2. As the baseball leaves the hand, it gains kinetic energy due to its motion (increased speed).

In a perfect scenario where height doesn't significantly change (like throwing at the same level), you could say the potential energy stays constant while the kinetic energy increases.

So, if we consider gravitational potential energy vs. kinetic energy upon the act of throwing when there isn't much vertical displacement, the answer would lean more towards kinetic energy increasing while potential energy remains constant rather than decreasing.

If the ball were dropped (rather than thrown) then potential energy would decrease and kinetic energy would increase (which aligns with option C).

Given the context of the throw, if we strictly focus on the mechanics:

  • The ball primarily gains kinetic energy due to the action of being thrown rather than a significant change in potential energy.

In conclusion, based on your question about being thrown and the context, the most accurate answer when considering height changes would align more with a scenario of constant potential energy and increasing kinetic energy, but if height were to decrease, then option C would apply in other contexts.

Thank you for your patience, and I'm here to clarify or expand on any points further!