To find the height of the ball 4 seconds after it has been thrown, we can plug in t = 4 into the function h(t) = -16t^2 + 72t.
So, h(4) = -16(4)^2 + 72(4) = -16(16) + 288 = -256 + 288 = 32.
Therefore, the height of the ball 4 seconds after it has been thrown is 32 feet.
When a ball is thrown up into the air, the function h(t) = −16t2 + 72t
gives the height h
in feet of the ball t
seconds after it has been thrown. Find the height of the ball 4 seconds after it has been thrown. (1 point)
Responses
32
32
4384
4384
48
48
288
288
1 answer