When a 9.00 kg mass is placed on top of a vertical spring, the spring compresses 4.5cm, FIND THE FORCE CONSTANT OF THE SPRING.

3 answers

I will be happy to critique your thinking.

I would use Hooke's law: F=kx
19.6
(9.00kg) x (9.81m/s^2)= 88.29

88.29/4.5= 19.62N/cm

or .1962N/m