the tea (water) loses the energy gained by the spoon
250.0 * (90.00 - 85.00) * 4.184
4 sig fig ... not 5 as in your answer
When a 37.00 g silver spoon, initially at room temperature, is placed into 250.0mL of 90.00oC tea, it reaches a temperature of 85.00°C. The spoon will have gained ? J of thermal energy.
I got 5237.5 Joules as (mass)x(specific heat capacity)x(Temperature change)=Heat,
which was apparently incorrect.
Please note that we are NOT given the specific heat capacity of silver in this question.
1 answer