Ask a New Question

When a 0.50 kg-object is attached to a vertically supported spring, it stretches 0.10 m from the equilibrium position. Find k for the spring.

1 answer

k = M*g/(length change) = 4.9/0.1
= 490 N/m

Ask a New Question or answer this question.

Similar Questions

When a .90 kg object is attached to a vertically supported spring, it stretches .15 m from the equilibrium position. Find k for
1. 0 answers
A steel spring is hung vertically. Using a ruler, the lower end of the spring was measured to be 25.0cm from its upper end.
1. 3 answers
A steel spring is hung vertically. Using a ruler, the lower end of the spring was measured to be 25.0cm from its upper end.
1. 1 answer
An object is attached to the lower end of a 100-coil spring that is hanging from the ceiling. The spring stretches by 0.210 m.
1. 3 answers

more similar questions