When 90 kJ is removed from a 2-kg copper bar its temperature drops from 200 degrees celcius to 85 degrees celcius what is the specific heat of the iron?

Answer 1

Q = M*C*(delta T)

Solve for C, with

deltaT = -115 C
Q = -90 kJ
M = 2.0 kg

Answer 2

0.391

Answer 3

0.39 kJ/kg degree C