when 8.28g of ethanol were heated with 60g of ethanioc acid 49.74 of acid remain at equilibrium calcuma the value of k

Answer 1

mols C2H5OH = grams/molar mass = ?
mols CH3COOH = grams/molar mass = ?

..C2H5OH + CH3COOH ==> CH3COOC2H5 + H2O
I..0.18......1.0.........0...........0
C...-x.......-x..........x...........x
E.0.18-x....1.0-x........x...........x

49.74/60 = about 0.829
so 1-x = 0.829 which makes x = 0.171
Substitute the values into the Kc expression and solve for Kc.