N2 + 3H2 ==> 2NH3
When gases are involved one may use a shortcut and use L as if they were mols.
This is a limiting reagent problem (LR) and you know that because amounts are given for BOTH reactants.
I do these the long way.
How much NH3 can be produced from 6 L N2 and all of the H2 needed. That is
6L x (2 mol NH3/1 mol H2) = 12 L NH3.
How much NH3 can be produced from 18 L H2 and all of the N2 needed. That is
18 x (2 mols NH3/3 mols H2) = 12 L NH3.
The numbers are the same so you will have 18 L NH3 produced.
When 6 liter of nitrogen gas reacts with 18
liters of hydrogen gas at constant temperature
and pressure, how many liters of ammonia gas
will be produced?
1 answer
2 answers