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When 6.0L of H2 reacts with 2.0L of N2, 4.0L of gaseous product are formed. All volumes of gases are measured at the same temperature and pressure. What is the formula of the product? Hint: Assume all reactants are consumed.

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6H2+2N2 >> 4 NxHy

so 12 H onleft, so x on right is 1
4N on left, so y=3
NH3

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