The heat of fusion of ice is calculated by dividing the energy absorbed by the number of moles of ice that have melted.
Given:
Number of moles of ice = 6.00 mol
Energy absorbed = 36.1 kJ = 36.1 * 10^3 J
Heat of fusion of ice = Energy absorbed / Number of moles of ice
Heat of fusion of ice = 36.1 * 10^3 J / 6.00 mol
Heat of fusion of ice = 6016.67 J/mol
Therefore, the experimental heat of fusion of ice is approximately 6016.67 J/mol.
When 6.00 mol of ice at 0.0°C melts completely without changing temperature, it absorbs 36.1 kJ of energy. The experimental heat of fusion of ice is
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