If the reaction is mole for mole, then y0u have the salt at the end of the reaction. Hydrolyze the salt (react it with water) and go from there.
NH4Cl ==> NH4^+ | Cl^-
The NH4^+ hydrolyzes.
NH4^+ + HOH ==> NH3 + H3O^+
Set up and ICE chart and solve for H3O^+ and from there you can get pH.
When 50.0mL of 0.100M NH3 (Kb=1.8x10^-5) solution is mixed with 20.0mL of of 0.250M HCl solution, what is the pH after reaction?
I solved the ka=5.56x10^-10 and I solved the moles of each nHCl and nNH3 and both have 0.005 moles. What do I do after this?
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1 answer