Yes it does.
From the problem, it says that 50 cm^3 of AgNO3 and 50 cm^3 of HCl are mixed. Therefore, the total volume of the solution is 50 + 50 = 100 cm^3.
Then an assumption is that the density of the solution is 1 g/ cm^3. We have the volume, we have the density, we can get the mass:
d = m/V
m = d * V
m = 1 g/cm^3 * 100 cm^3
m = 100 g (mass of the solution)
To find the heat, the formula for heat absorbed/released is
q = mc(T2 - T1)
where
m = mass (in g)
c = specific heat capacity (J/g-K) = 4.184 J/g-K (for water)
T = temperature
Substituting, you'll get the expression you typed for the answer:
q = 100 * 4.184 * (20.35 - 20)
Hope this helps :3
When 50.0 cm3 of 0.100 mol dm-3 AgNO3 is mixed with 50.0 cm3 of 0.0500 dm-3 HCl in a polystyrene cup, the temperature increases from 20.00°C to 20.35°C. Assume that the specific heat capacity of the solution is the same as that of water, and that the density of the solution is 1.0 g cm-3. What is the value of ΔH for the reaction shown below?
AgNO3(aq) + HCl(aq) AgCl(s) + HNO3(aq)
The answer says...
To find heat.. q=100.0x4.18x0.35
And so on.....
BUT WHAT I DON'T UNDERSTAND IS WHERE DOES 100.0 COME FROM.... THE PROBLEM STATES 1.0 g cm^-3....SO IS IT 100.0 GRAMS??? HOW MANY GRAMS ARE IN 1 g cm ^-3??? DO I HAVE TO CONVERT... IF SO... HOW AND TO WHAT UNIT??????
1 answer
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