Lets check to see if there is a limiting reageant.
Four volumes of ammonia, five volumes of O2
5/4 *34.5=43 L O2, so there is not enough oxygen.
4/5*39.5=31.6 L of ammonia are reacted.
Liters of NO produced: 31.6L NO
moles: 31.6/22.4
You figure the grams.
When 34.5 L ammonia and 39.5 L oxygen gas at STP burn, nitrogen monoxide and water are produced. After the products return to STP, how many grams of nitrogen monoxide are present?
4NH3+5O2->4NO+6H2O
1 answer
1 answer