When 30.0 grams of aluminum reacts with HCl how many grams of aluminum chloride are formed? Al = HCl yields AlCl3 + H 2

Answer 1

the mol wt of Al is 27

30g of Al = 1.11 mol

so, we end up with 1.11 mol of AlCl3

that would be 1.11(27 + 3*35.45) = 148g