When 3.89 g of a nonelectrolyte solute is dissolved in water to make 835 mL of solution at 26 °C, the solution exerts an osmotic pressure of 825 torr.

Question

When 3.89 g of a nonelectrolyte solute is dissolved in water to make 835 mL of solution at 26 °C, the solution exerts an osmotic pressure of 825 torr.
What is the molar concentration of the solution?
How many moles of solute are in the solution?
What is the molar mass of the solute?

DrBob222 · Answer

pi = nRT Substitute and solve for n = mols Then M = mols/L solution # mols = M x L = ? molar mass = grams/mols.