When 3.50 LITERS of N2H4react with 3.5 LITERS of N2O4, how many LITERS of N2will be produced at STP
6 answers
I did this down below :)
Hey, I am just an old retired physicist. I do not work fast.
Now check my arithmetic carefully because my brain is a bit fuzzy.
Once again :
3NO2+ 1H2O ------> 1NO + 2HNO3
How many moles of NO2 in 9 liters at stp?
9 L * 1 mol / 22.4 L = 0.401 mols
If that is liquid water it is about (7 /1000) meters^3
water mass is about 1000 kg/m^3 so about 7 kg = 7000 grams
mol H2O is 2+16 = 18 g /mol
so we have an excess of water, use 0.301 mols NO2
for every 3 liters of NO2 we get ONE liter of NO
so Three
3NO2+ 1H2O ------> 1NO + 2HNO3
How many moles of NO2 in 9 liters at stp?
9 L * 1 mol / 22.4 L = 0.401 mols
If that is liquid water it is about (7 /1000) meters^3
water mass is about 1000 kg/m^3 so about 7 kg = 7000 grams
mol H2O is 2+16 = 18 g /mol
so we have an excess of water, use 0.301 mols NO2
for every 3 liters of NO2 we get ONE liter of NO
so Three
The same way.
2 N 2 H 4 + N 2 O 4 → 3 N 2 + 4 H 2 O
note you need 2 liters of the first for 1 of the second
so N2H4 governs the problem
we get 3 liters of N2 for every 2 liters of N2H4
so
(3/2)(3.5) Liters
note you need 2 liters of the first for 1 of the second
so N2H4 governs the problem
we get 3 liters of N2 for every 2 liters of N2H4
so
(3/2)(3.5) Liters
2 answers