When 3.00g of calcium chloride were reacted in an excess of silver nitrate, 6.4g of AlCl
were produced. What was the percent yield in this reaction?
2 answers
is this from a CA lesson?
CaCl2 + 2AgNO3 → 2AgCl + Ca(NO3)2
3.00g CaCl2 is 0.027 moles
So you expect 0.054 moles of AgCl
6.4g AgCl is 0.0446 moles
so the yield is 0.446/0.054 = 82.7%
3.00g CaCl2 is 0.027 moles
So you expect 0.054 moles of AgCl
6.4g AgCl is 0.0446 moles
so the yield is 0.446/0.054 = 82.7%