2Na + Cl2 ==> 2NaCl
Convert mols Na t mols NaCl. That's
3.0 mols Na x (2 mols NaCl/2 mols Na) = 3 mols NaCl
g NaCl = mols NaCl x molar mass NaCl = about 175g (estimated). That is the theoretical yield(TY). The actual yield (AY) is 145.8. Note that the TY above is estimated so you need to go through the math and obtain an accurate answer.
%yield = (AY/TY)*100 = ?
When 3.00 moles of sodium are reacted with large amounts of chlorine gas 145.8 g of sodium chloride are produced determine percentage yield
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