find the deltaH per gram NaOH.
it must be 1/2 ((149*cwater*5)+11*5)
now multiply by the mol mass of NaOH (40).
when 2g of NaOH were dissolved in 149 g of H2o in a calorimeter at 24 degrees C the temperature of the solution went up to 29 degrees C. If the calorimeter constant was 11 cal/C find delta H for the solution of one mole of NaOH in H2O
3 answers
this does not help . . . . can any one else help me please
q = heat to water + heat to calorimeter
q = [(mass H2O x specific heat H2O x (Tfinal-Tinitial)] + [Ccal*(Tfinal-Tinital)]
Then dH in cal/g= q/2g
and dH in cal/mol = cal/g x molar mass NaOH
q = [(mass H2O x specific heat H2O x (Tfinal-Tinitial)] + [Ccal*(Tfinal-Tinital)]
Then dH in cal/g= q/2g
and dH in cal/mol = cal/g x molar mass NaOH