Question

when 2 moles of potassium chlorate crystals decompose to potassium chloride crystals and oxygen gas at a constant pressure and temperature, 78.0 kj of heat is given off. write a thermodynamic equation for this reaction.I don't know how to set up the equation i know that for the potassium there would have to be 2 for every one oxygen and 1 potassium in the product side but how to i balance or use the correct nomenclature

Answer 1

2KClO3 ==> 2KCl + 3O2 dH = -78 kJ

or
you could write
KClO3 ==> KCl + 3/2 O2 dH = -39 kJ/mol