K2CO3+ HCl (aq)>>CO2+K2O+H2O> KOH +CO2
Note the second reaction is with K2O with the water that accompanies the acid. 2M HCl is mostly water.
when 2.76 (0.0200 mol) of k2co3 was mixed with 30.0 ml of approximately 2 M HCL the temperature rose by 5.2 C
how do i write a balanced equation for problems like this?
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