When 2.75 dm3 of O2 react with an excess of glucose (C6H12O2), according to the reaction below, what volume of carbon dioxide will be produced?

Question

6O2(g) + C6H12O6(s) ---> 6H2O(g) + 6CO2(g)

Answer 1

6O2(g) + C6H12O6(s) ---> 6H2O(g) + 6CO2(g)
When dealing with gases one may take a shortcut and use volume as mols; therefore, 2.75 cm^3 x (6 mols CO2/6 mols O2) = 2.75 cm^3 CO2