When .1625 g of Magnesium is burned in a bomb container that has a heat capacity of 3.03 kJ/ºC, the temperature increases by 1.252 ºC. How much heat (kJ/mol) is liberated during the burning of magnesium?
Just want to make sure I am doing this correctly:
q = ms∆T
q = (.1625g Mg) (3.03) (1.252ºC)
q = .6165 kJ/g --> kJ/mol ??
2 answers
I didn't check the math but the method looks ok to me.
So, essentially .6164 kJ/g --> kJ/mol
.6165/24.31 = .0254 kJ/g
.6165/24.31 = .0254 kJ/g