This is worked almost the same as the one above. See
https://www.jiskha.com/questions/1856330/what-is-the-final-temperature-of-a-mixture-of-250-g-of-water-at-33-c-into-which-3-g-of
Just omit the part from -20 T to 0C and start with the melting of ice @ 0C.
So it will be mass(250 g) water x specific heat water x (Tfinal-Tinitial)] + [mass melted ice(16 g) x specific heat water x (Tfinal-Tinitial)] +(mass ice x heat fusion @ 0C) = 0 and solve for Tfinal.
When 16 g of ice at 0°C is dropped into 250 g of water at 42°C, what would be the final temperature?
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