Q=cmΔT= 4186•0.6•20 = 50232 J.
ΔQ=Q₀-Q=140000-50232=89768 J
m₁=ΔQ/λ=89768/335000=0.268 J
M=0.6-0.268=0.332 kg
When 140000 joules of heat is removed from 0.60kg of water initially at 20Celsius, will all the water freeze? If not how much remains unfrozen
1 answer