When 1.60 multiplied by 105 J of heat enters a cherry pie initially at 20.0°C, its entropy increases by 470 J/K. What is its final temperature (C)?
Drwls answered:
delta S = entropy change = 1.6*10^5*[1/293 - 1/T2] = 470
Solve for T2
But after I checked the answer, it is not correct.