When 1.187g of a metallic oxide is reduced with excess hydrogen, 1.054g of the metal is produced. How do you determine what the metal oxide is?
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Ok, so in order to identify the metal oxide, you first start by taking 1.187g-1.054 to find the g of O2. getting .133, you then determine the moles by dividing by mm of O2=.0083125. Then, because it is a metal oxide, multiply the moles of O2 by 2. Then take the 1.054g and divide it by .0083 to get 63.4, which is Copper.
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