When 1.00 kg lead (specific heat = 0.13 J g -1 C -) at 100.0 C is added to a quantity of water at 28.5C, the final temperature of the lead-water mixture is 35.2 C. What is the mass of water present?
4 answers
3.21grams
sorry the answer is actually about 300grams
16.2g
How can we solve this question
6 answers