Asked by Casey
When 0.668 L of Ar at 1.20 atm and 227°C is mixed with 0.258 L of O2 at 501 torr and 127°C in a 400 mL flask at 27°C, what is the pressure in the flask?
Pressure is given for both, am I supposed to use v1p1/t1 = v2p2/t2?
Some reason this really doesn't make sense to me. Help is seriously appreciated.
Pressure is given for both, am I supposed to use v1p1/t1 = v2p2/t2?
Some reason this really doesn't make sense to me. Help is seriously appreciated.
Answers
Answered by
DrBob222
No, the (P1V1/T1) thing won't get it. You have two gases with P, T, and V given. I would calculate n for each using PV = nRT, add n for one to n for the other, then plug the total n back into a new PV = nRT where the new V is the 400 mL flask @ 27 C.
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