balance the equation. I bet you get four moles of CO2 and 5 moles of water for each mole of butane. If that is true, then you must use 4O2+5(1/2O2) of oxygen, or 6.5 moles O2 for each mole of butane. So you had .340moles, and that multiplied by 6.5 is ...
Balance the equation and see
When 0.340 mol of butane, C4H10, are burned with excess oxygen giving CO2 and H2O, how many moles of oxygen are consumed?
4 answers
wrong
12
13.0