when 0.20 mole HF is dissolved in water to a volume of 1.00 L, 5.8% of the HF dissociates to form F- (aq). What is the equilibrium constant for the reaction ?
HF(aq) +H2O(l) ------ F- (aq) +H3O+ (aq)
1 answer
I worked this below. Try one of your earlier posts. I can look for a link if you can't find it.