When 0.100 L of 0.200 M K2C2O4 react with 0.150 L of 0.250 M BaBr2, BaC2O4 forms an insoluble precipitate. Calculate the final concentrations of the ions that remain in solution after the reaction.

I know how to get the net ionic equation (Ba2+ + C2O4- -> BaC2O4).

HOWEVER - I don't know why the three ions that remain in solution are K+, Br-, and Ba2+. Where did K+ come from? Thanks!

1 answer

K, Br are ions because the compounds formed go into solution as ions.
Ba ion is there because there is excess Ba ions. Look at the balanced equation.
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