When 0.076 moles of lead(II) nitrate are dis-

solved in enough water to make 670 mililiters
of solution, what is the molar concentration
of nitrate ions?
Answer in units of M

3 answers

What's wrong with using M = moles/L soln? That will be M = 0.076/0.670 = ?
That is the molarity of lead(II)nitrate I need to find it for nitrate ions
There are two nitrate ions in one molecule of Pb(NO3)2; therefore, M Pb(NO3)2 x 2 = M NO3^-