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When 0.03 moles of aluminum sulfate are dissolved in enough water to make 266 mililiters of solution, what is the molarity of sulfate ions?

Answer in units of M

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Al2(SO4)3 = 0.03 mols
M Al2(SO4)3 = 0.03/0.266L = about 0.113
M SO4^2- = 3x that.

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