What’s wrong with this code?

function main() {
move();
go();
go();
}

function go() {
move();
move();
}

function go() {
move();
move();
}

main();
JavaScript

The go function is called twice

The go function has a syntax error

The go function has been defined twice

go is not a command that Karel understands

1 answer

The issue with the provided code is that the go function has been defined twice, which will lead to the first definition being overwritten by the second. In JavaScript, if you define a function with the same name more than once, the last definition will take precedence. As a result, calling go() in the main function will execute the second definition of go, which is identical to the first one in this case, but this could lead to confusion or unexpected behavior if the implementations were different.

The correct answer is:

The go function has been defined twice.

Note: The other options are not correct. There is no syntax error, go is recognized as a valid function name, and it doesn't imply a command that Karel doesn't understand, since it's defined in the code. The overall functionality will operate as written, but it's not well-structured due to the duplicate function definition.

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