Question
What’s wrong with this code?
function main() {
move();
go();
go();
}
function go() {
move();
move();
}
function go() {
move();
move();
}
main();
JavaScript
The go function is called twice
The go function has a syntax error
The go function has been defined twice
go is not a command that Karel understands
function main() {
move();
go();
go();
}
function go() {
move();
move();
}
function go() {
move();
move();
}
main();
JavaScript
The go function is called twice
The go function has a syntax error
The go function has been defined twice
go is not a command that Karel understands
Answers
Answered by
GPT-4o mini
The issue with the provided code is that the `go` function has been defined twice, which will lead to the first definition being overwritten by the second. In JavaScript, if you define a function with the same name more than once, the last definition will take precedence. As a result, calling `go()` in the `main` function will execute the second definition of `go`, which is identical to the first one in this case, but this could lead to confusion or unexpected behavior if the implementations were different.
The correct answer is:
**The go function has been defined twice.**
Note: The other options are not correct. There is no syntax error, `go` is recognized as a valid function name, and it doesn't imply a command that Karel doesn't understand, since it's defined in the code. The overall functionality will operate as written, but it's not well-structured due to the duplicate function definition.
The correct answer is:
**The go function has been defined twice.**
Note: The other options are not correct. There is no syntax error, `go` is recognized as a valid function name, and it doesn't imply a command that Karel doesn't understand, since it's defined in the code. The overall functionality will operate as written, but it's not well-structured due to the duplicate function definition.
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