2NaOH + H2SO4 ==> Na2SO4 + 2H2O
mols H2SO4 = M x L = 1 x 2 = 2
mols NaOH = M x L = 1 x 0.02 = 0.02
All of the NaOH is used; it neutralizes 0.02 x 1/2 = 0.01 mols of H2SO4. That leaves how much H2SO4. That's 2-0.01 = 1.99
What's the volume? That's 2000 mL H2SO4 + 20 mL NaOH = 2020 mL total solution or 2.02 L.
M H2SO4 left = mols H2SO4/L solution = ?
What's the resulting solution if 2000cm3 of 1MH2S04 is mixed with 20cm3 of 1M NaOH? i got 0.5M,acidic in concentration.
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