what's the distance between (19, -6) and (8, -6) on a coordinate plane?

Answer 1

The distance between two points on a coordinate plane can be calculated using the distance formula:

√((x2 - x1)^2 + (y2 - y1)^2)

Plugging in the coordinates (19, -6) and (8, -6) into the formula:

√((8 - 19)^2 + (-6 - (-6))^2)
= √((-11)^2 + (0)^2)
= √(121)
= 11

Therefore, the distance between the points (19, -6) and (8, -6) on a coordinate plane is 11 units.