what's the base and the exponent of 1^9 times 1^8

Answer 1

To simplify the expression \(1^9 \times 1^8\), we can use the property of exponents that states \(a^m \times a^n = a^{m+n}\).

In your case, both terms have a base of 1:

\[ 1^9 \times 1^8 = 1^{9+8} = 1^{17} \]

So, the base is \(1\) and the exponent is \(17\).