The equation for a line passing through two points (x₁, y₁) and (x₂, y₂) can be found using the slope-intercept form:
y = mx + b
where m is the slope of the line and b is the y-intercept.
Using the points (0, -2) and (4, 0):
slope (m) = (change in y) / (change in x)
= (0 - (-2)) / (4 - 0)
= 2 / 4
= 1/2
Now, substitute the values of the slope and one of the given points (0, -2) into the slope-intercept form to find the y-intercept:
-2 = (1/2)(0) + b
-2 = 0 + b
b = -2
Therefore, the equation of the line is:
y = (1/2)x - 2
what's A line that contains the points (0, -2) and (4, 0).
1 answer