To solve \( 1 \frac{1}{2} - \frac{3}{4} \), first convert \( 1 \frac{1}{2} \) to an improper fraction.
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Convert \( 1 \frac{1}{2} \): \[ 1 \frac{1}{2} = \frac{2 \times 1 + 1}{2} = \frac{2 + 1}{2} = \frac{3}{2} \]
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Now subtract \( \frac{3}{4} \) from \( \frac{3}{2} \). To do this, we need a common denominator. The least common denominator (LCD) of 2 and 4 is 4.
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Convert \( \frac{3}{2} \) to have a denominator of 4: \[ \frac{3}{2} = \frac{3 \times 2}{2 \times 2} = \frac{6}{4} \]
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Now subtract \( \frac{3}{4} \): \[ \frac{6}{4} - \frac{3}{4} = \frac{6 - 3}{4} = \frac{3}{4} \]
Thus, the answer is \( \frac{3}{4} \).