We don't do homework but we can help you understand. What about the problem do you not understand? Do you know to look up the cell potential for the Mn to Mn^+2 and add it to the cell potential for the Ce^+4 ==>Ce^+3?
That should give you the cell potential for the reaction. Post your work if you get stuck.
What would the standard cell potential in volts be for
Mn(s) + 2Ce4+(aq) -> Mn2+(aq) + 2Ce3+(aq)?
3 answers
The two values I got for those cell potentials were 1.61 (Ce^4+ + 2e- -> Ce^3+) and -1.18 for Mn^2+ + 2e^- -> Mn. Which equals 0.43V.
I wasn't sure if I double the value for Ce^4 ... as they have 2's at front of them?
I wasn't sure if I double the value for Ce^4 ... as they have 2's at front of them?
No, you do not double the value for Ce^+4. Sorry it took me so long to get back to you.
1 answer