What would Qc be if the volume of the container decreased by a factor of 1.774 for the following reaction?

Question

What would Qc be if the volume of the container decreased by a factor of 1.774 for the following reaction?
PH3(g) + BCl3(g) → PH3BCl3(s)		
KC = 534.8
at 353.0oC

DrBob222 · Answer

If the volume decreases (by say a factor of 2) that will double the (PH3) and double (BCl3). For a factor of 1.774 concn will be increased for EACH by 1.774. Remember the solid doesn't appear in Kc.
Kc = 1/(PH3)(BCl3)
So Kc > Q = 534.8/(1.774)(1.774)