Given the information provided, we can prove that the parallelogram PWRS is a rhombus by showing that all four sides are congruent.
1. Length of QR and PS is 2.2: This indicates that QR and PS have the same length, which means opposite sides of the parallelogram are congruent.
2. Slope of QR and PS is -2 and Slope of RS and QP is -1/2: Since opposite sides of a rhombus are parallel, the slopes being equal demonstrates that the sides are parallel to each other.
3. Length of QR is 2.2 and slope of QR is -2: This confirms that QR is a diagonal of the parallelogram and that it divides the parallelogram into two congruent triangles.
4. Length of QS and PR is 4.2: The fact that the diagonals QS and PR have equal length indicates that the diagonals of the parallelogram are congruent and bisect each other at right angles, which is a property of rhombuses.
Based on this evidence, we can conclude that the parallelogram PWRS is a rhombus.
What would prove the parallelogram PWRS is a rhombus?
P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)
What would prove the parallelogram PWRS is a rhombus?
P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)
Length of QR and PS is 2.2 and Length of RS and QP is 2.2
Slope of QR and PS is -2 and Slope of RS and QP is -1/2
Length of QR is 2.2 and slope of QR is -2
Length of QS and PR is 4.2
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